Acceleration is defined as the rate of change of velocity. Suppose we call the rate of change of acceleration as ` SLAP ? ` (i) What is the unit of `SLAP` . (ii) How can we calculate instantaneous SLAP ?
Text Solution
Verified by Experts
The correct Answer is:
A
At maximum height `v_(y)=0` `rArr H_("max")=(u^(2) sin^(2) theta)/(2g)=g/8(t_(1)+t_(2))^(2)`
Topper's Solved these Questions
MOTION IN A PALNE
ALLEN |Exercise EXERCISE-04[A]|35 Videos
MOTION IN A PALNE
ALLEN |Exercise Exercise-04[B]|14 Videos
MOTION IN A PALNE
ALLEN |Exercise Comprehension#6|4 Videos
KINEMATICS-2D
ALLEN |Exercise Exercise (O-2)|47 Videos
NEWTON'S LAWS OF MOTION & FRICTION
ALLEN |Exercise EXERCISE (JA)|4 Videos
Similar Questions
Explore conceptually related problems
The acceleration which can change only the direction of velocity of a body is called
What is the rate of change of the volume of sphere w.r.t. its surface area when its radius is 2 units ?
Distance is a scalar quantity. Displacement is a vector quqntity. The magnitude of displacement is always less than or equal to distance. For a moving body displacement can be zero but distance cannot be zero. Same concept is applicable regarding velocity and speed. Acceleration is the rate of change of velocity. If acceleration is constant, then equations of kinematics are applicable for one dimensional motion under the gravity in which air resistance is considered, then the value of acceleration depends on the density of medium. Each motion is measured with respect of frame of reference. Relative velocity may be greater // smaller to the individual velocities. A person is going 30 m north, 20m east and then 30sqrt(2) m southwest. The net displacement will be
Distance is a scalar quantity. Displacement is a vector quqntity. The magnitude of displacement is always less than or equal to distance. For a moving body displacement can be zero but distance cannot be zero. Same concept is applicable regarding velocity and speed. Acceleration is the rate of change of velocity. If acceleration is constant, then equations of kinematics are applicable for one dimensional motion under the gravity in which air resistance is considered, then the value of acceleration depends on the density of medium. Each motion is measured with respect of frame of reference. Relative velocity may be greater // smaller to the individual velocities. A particle moves from A to B. Then the ratio of distance to displacement is :-
Distance is a scalar quantity. Displacement is a vector quqntity. The magnitude of displacement is always less than or equal to distance. For a moving body displacement can be zero but distance cannot be zero. Same concept is applicable regarding velocity and speed. Acceleration is the rate of change of velocity. If acceleration is constant, then equations of kinematics are applicable for one dimensional motion under the gravity in which air resistance is considered, then the value of acceleration depends on the density of medium. Each motion is measured with respect of frame of reference. Relative velocity may be greater // smaller to the individual velocities. A particle is moving along the path y=4x^(2) . The distance and displacement from x=1 to x=2 is (nearly) :-
A particle moves in such a way that its position vector at any time t is vec(r)=that(i)+1/2 t^(2)hat(j)+that(k) . Find as a function of time: (i) The velocity ((dvec(r))/(dt)) (ii) The speed (|(dvec(r))/(dt)|) (iii) The acceleration ((dvec(v))/(dt)) (iv) The magnitude of the acceleration (v) The magnitude of the component of acceleration along velocity (called tangential acceleration) (v) The magnitude of the component of acceleration perpendicular to velocity (called normal acceleration).
A particle is travelling in a circular path of radius 4m . At a certain instant the particle is moving at 20m/s and its acceleration is at an angle of 37^(@) from the direction to the centre of the circle as seen from the particle (i) At what rate is the speed of the particle increasing? (ii) What is the magnitude of the acceleration?
A player throwsa a ball upwards with an initial speed of 29.4 ms^(-1) . (i) What is the direction of acceleration during the upwared motion of the ball? (ii) What are the velocity and acceleration of the ball at the highest point of its motion? (iii) Choose the x=0 and t=0 to be the location and time of the ball at its highest point, vertically downward direction to be the positive direction of X-axis, and give the signs of positive, velocity and acceleration of the ball during its upward, and downward motion. (iv) To what height does the ball rise and after how long does the ball return to the player's hand?( Take g =9.8 ms^(-2) , and neglect air resistance).