Three particles P, Q and R are situated at point A on the circular path of radius 10m. All three particles move along different path and reach at point B shown in figure. Then the ratio of distance traversed by particle P and Q is:-
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The correct Answer is:
B
At maximum range vertical displacement `=0` `rArr t'=(2u sin theta)/g`. So range R `(u cos theta)((2u sin theta)/g)-1/2 a((2u sin theta)/g)^(2)` `=(2u^(2) sin theta cos theta)/g(g/a-tan theta)`
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