Home
Class 11
PHYSICS
A ball is thrown upwards from th top of ...

A ball is thrown upwards from th top of a tower 40 m high with a velocity of `10m//s`. Find the time when it strikes the ground `(g=10m//s^(2))`

Text Solution

Verified by Experts

In the problem `u= + 10 m//s, a =-10 m//s^(2) and s =- 40 m ` ( at the point where ball strikes the ground)
Substituting in` s = ut +(1)/(2) at^(2)`
`-40= 10t - 5t^(2) or 5t^(2) -10t -40=0 or t^(2) - 2t -8 =0`
Solving this we have t= 4 s and -2 s. Taking the positive value t = 4s.
Promotional Banner

Topper's Solved these Questions

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN |Exercise BEGINNER S BOX-1|6 Videos

  • KINEMATICS (MOTION ALONG A STRAIGHT LINE AND MOTION IN A PLANE)

    ALLEN |Exercise BEGINNER S BOX-2|7 Videos

  • KINEMATICS

    ALLEN |Exercise EXERCISE-2|89 Videos

  • MISCELLANEOUS

    ALLEN |Exercise Question|1 Videos

Similar Questions

Explore conceptually related problems

A ball is thrown upwards from the top of a tower 40 m high with a velocity of 10 m//s. Find the time when it strikes the ground. Take g=10 m//s^2 .

A ball is thrown from the top of a 60m high tower with velocity 20sqrt(2)m//s at 45^(@) elevation of path at highest point. ( g=10m//s^(2) )

A ball is thrown upward from edge of a cliff with an intial velocity of 8 m/s. How fast is it moving half second later ? (g=10 m/s^(2))

A particle is projected from a tower as shown in figure, then find the distance from the foot of the tower where it will strike the ground. (g=10m//s^(2))

A ball is thrown upward from edge of a cliff with an intial velocity of 6 m/s. How fast is it moving 1/2 s later ? (g=10 m/s^(2))

A particle is dropped from the top of a tower. It covers 40 m in last 2s. Find the height of the tower.

A ball is projected upwards from the top of a tower with a velocity 50ms^-1 making an angle 30^@ with the horizontal. The height of tower is 70m. After how many seconds from the instant of throwing, will the ball reach the ground. (g=10 ms^-2)

A pebbel is thrown horizantally from the top of a 20 m high tower with an initial velocity of 10 m//s .The air drag is negligible . The speed of the peble when it is at the same distance from top as well as base of the tower (g=10 m//s^2)

A particle of mass 50 g is projected horizontally from the top of a tower of height 50 m with a velocity 20m//s . If g=10m//s^(2) , then find the :-

A particle is projected vertically upwards from ground with velocity 10 m // s. Find the time taken by it to reach at the highest point ?