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A Juggler throws balls into air. He thro...

A Juggler throws balls into air. He throws one ball whenever the previous one is at its highest point. How high do the balls rise if he throws n balls each second. Acceleration due to gravity is g.

Text Solution

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Juggler throws n balls in one second so time interval between two consecutive throws is `t = (1)/(n)s ` each ball takes `(1)/(n) s` to reach maximum height
So `h_(max)= (1)/(2) xx "gt"^(2) = (1)/(2) xx g ((1)/(n))^(2)`
`h_(max)= (g)/(2n^(2))`
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