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A balloon starts rising from the ground ...

A balloon starts rising from the ground with an acceleration of 1.25 `m//s^(2)` . A stone is released from the balloon after 10s. Determine
(1) maximum height of ston from ground
(2) time taken by stone to reach the ground

Text Solution

Verified by Experts

Velocity of balloon after 10 sec. = `0= 1.25 xx 10`
`" " = 12. 5 m//s`
distance travelled `= (1)/(2) at ^(2) = (1)/(2) (1.25) xx 10^(2)`
`" " = 62.5` m

(i) `h= (u^(2))/(2g)`
` = ((12.5)^(2))/(20) = 7. 8125` m
height from ground = `62.5 + 7.8125 = 70.31`m
(ii) `t_(OA) = (u)/(g) = (12. 5)/(10) = 1.25 sec`.
`t_(AB) = sqrt((2h_(AB))/(g)) = 3.75 sec`.
Total time = 5 sec.
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