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If the dimensions of a physical quantity...

If the dimensions of a physical quantity are given by `M^(a)L^(b)T^(c)`. Then the physical quantity will be:

A

Force if a = 0, b = -1, c =-2

B

Pressure if a = 1, b =-1, c = -2

C

Velocity if a =1, b =0, c=-1

D

Acceleration if a = 1, b=1, c=-2

Text Solution

Verified by Experts

The correct Answer is:
B
[Force ] = `[MLT^(-2)]`
[Pressure] = `[ML^(-1)^(-2)]`
[Velocity] = `[LT^(-1)]`
[Acceleration] = `[LT^(-2)]`
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  1. If the dimensions of a physical quantity are given by M^(a)L^(b)T^(c)....

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