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If E is the electric field intensity eps...

If E is the electric field intensity `epsilon_(0)` is the permitivity of free space, then find dimensions of quantity `epsilon_(0) E^(2)`.

A

`[MLT^(-1)]`

B

`[ML^(2)T^(-2)]`

C

`[ML^(-1)T^(-2)] `

D

`[ML^(2)T^(-1)]`

Text Solution

Verified by Experts

The correct Answer is:
C
`(1)/(2) in_0 E^(2)` = Energy density = `("Energy")/("Volume")= [M^(1)L^(-1)T^(-2)]`
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  1. If E is the electric field intensity epsilon(0) is the permitivity of ...

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