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The Henry's law constant for solubility ...

The Henry's law constant for solubility of `N_(2)` gas is water at `298K` is `10^(5)` atm. The % by volume of `O_(2)` is `20%` and % by volume of `N_(2)` is 80% in air. The mole of `N_(2)` dissolved in `90gm` of water is `x xx 10^(-y)` at `298K` and 10 atm pressure. Calculate the value of `x+y`.

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