An electron in a hydrogen like atom is i...

An electron in a hydrogen like atom is in excited state and has total energy `-3.4 eV`. The kinetic energy and `lamda_(db)` of electron are:

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An electron, in a hydrogen like atom , is in excited state. It has a total energy of -3.4 eV , find the de-Broglie wavelength of the electron.

In an excited state of hydrogen like atom an electron has total energy of -3.4 eV . If the kinetic energy of the electron is E and its de-Broglie wavelength is lambda , then

The total energy of an electron in the first excited state of the hydrogen atom is about –3.4 eV. (a) What is the kinetic energy of the electron in this state? (b) What is the potential energy of the electron in this state? (c) Which of the answers above would change if the choice of the zero of potential energy is changed?

A particular hydrogen like atom has its ground state Binding energy = 122.4 eV . It is in ground state. Then

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An electron in hydrogen atom first jumps from second excited state to first excited state and then from first excited state to ground state. Let the ratio of wavelength, momentum and energy of photons emitted in these two cases be a, b and c respectively, Then

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