The potential energy of a particle varies with distance `x` from a fixed origin as `U = (A sqrt(x))/( x^(2) + B)`, where `A and B` are dimensional constants , then find the dimensional formula for `AB`.

Options

A. `[ML^(7//2)T^(-2)]`
B. `[ML^(11//2)T^(-2)]`
C. `[M^(2)L^(9//2)T^(-2)]`
D. `[ML^(13//2)T^(-3)]`

Answer

B