Home
Class 12
PHYSICS
Find the minimum value of horizontal for...

Find the minimum value of horizontal force (F) required on the block of mass m to keep it at rest on the wall. Given the coefficient of friction between the surfaces is `mu`.

Text Solution

Verified by Experts

The correct Answer is:
`F=(mg)/(mu)`
Promotional Banner

Topper's Solved these Questions

  • RACE

    ALLEN |Exercise Basic Maths (WORK POWER & ENERGY)|33 Videos
  • RACE

    ALLEN |Exercise Basic Maths (CIRCULAR MOTION)|16 Videos
  • RACE

    ALLEN |Exercise Basic Maths (NEWTONS LAWS OF MOTION)|49 Videos
  • NEWTONS LAWS OF MOTION

    ALLEN |Exercise EXERCISE-III|28 Videos
  • SIMPLE HARMONIC MOTION

    ALLEN |Exercise Example|1 Videos

Similar Questions

Explore conceptually related problems

Mass moves on a slope making an angle 9 with the horizontal and is attached to mass m_(2) by a string passing over a frictionless pulley . The coefficient of friction between nq and the sloping surface is mu . Which of the following statements are true ?

force F = 100 N is applied horizontally on a block of mass 4 kg. Which is in contact with a wall. Such that it does not fall. The coefficient of friction between the block and the wall is

A block A with mass 100kg is resting on another block B of mass 200kg. As shown in figure a horizontal rope tied to a wall hold it. The coefficient of friction between A and B is 0.2 while coefficient of friction between B and the ground is 0.3 . the minimum required force F to start moving B will be.

A block is released on the slant face of a wedge of equal mass placed on a horizontal floor. The slant face of the wedge makes an angle of 45^(@) with the floor. Coefficient of friction between all surfaces in contact is the same. Different value/ range of coefficient of friction is given in column I and corresponding consequences in column II and III (wedge is fress to move) {:(,"Column-I",,"Column-II",,"Column-III",),((I),mu=0,(i),"Work done by friction on block and wedge is negative (on each)",(P),"Centre of mass of system (block+wedge) moves rightward and downward",),((II),mu gt 1,(ii),"Work done by friction on block is negative but on wedge it is zero",(Q),"Centre of mass of system (block+wedge) moves leftward and downward",),((III),sqrt(5)-2 lt mu lt 1,(iii),"Work done by friction on block and wedge is zero (on each)",(R ),"Centre of mass of system (block+wedge) remains at rest",),((IV),mu lt sqrt(5) - 2,(iv),"Friction between the block and wedge is static and between the wedge and ground it is kinetic in nature.",(S),"Centre of mass of system (block+wedge) moves vertically downward",):} Which of the following options is the correct representation of the case that the wedge remains motionless and the block slides down

A box of mass m is initially at rest on a horizontal surface. A constant horizontal force of mg/2 is applied to the box directed to the right. The coefficient of friction of the surface changes with the distance pushed as mu=mu_(0)x where x is the distance fr4om the initial location . For what distance is the box pushed until it comes to rest again?

A rocket is fired vertically from the earth with an acceleration of 2g, where g is the gravitational acceleration. On an inclined plane inside the tocket, making an angle theta with the horizontal, a point object of mass m is kept, the minimum coefficient of friction mu_(min) between the mass and the inclined suface such that the mass does not move is:

Acceleration of block A varies with time as shown in figure the value of coefficient of kinetic friction between block A and B is

A block lying on a rough horizontal surfaces as show in figure . Its mass is M and it is dispalced through a distance d by a force vec(F ) acting at an angle theta with horizontal . If mu is the coefficient of friction between a block and the surface and mass of block is M . then work done is ...........

A block of mass m lying on a rough horizontal plane is acted upon by a horizontal force P and another force Q inclined at an angle theta to the vertical. The minimum value of coefficient of friction of friction between the block and the surface for which the block will remain in equilibrium is

Two bars of masses m_(1) and m_(2) connected by a non - deformed light spring rest on a horizontal plane. The coefficient of friction between the bars and the surface is equal to mu . What minimum constant force has to be appled in the horizontal direction to the bar of mass m_(1) in order to shift the other bar?