Ammonia and oxygen react at high temperature as :
` 4NH_3 (g) +5O_2 (g) to 4 NO(g) +6H_2 O(g)`
In an experiment, rate of formation of NO is `2.4 xx 10^(-3) ` mol `L^(-) s^(-)` . Calculate
rate of formation of water.

Explanation

To solve the problem, we need to determine the rate of formation of water (H₂O) from the given reaction and the rate of formation of nitrogen monoxide (NO).

### Step-by-Step Solution:

1. **Write the balanced chemical equation:**
\[ 4NH_3 (g) + 5O_2 (g) \rightarrow 4NO(g) + 6H_2O(g) \]
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