For a first order reaction show that time required for 99% completion is twise the time required for the complation of 90% of reaction .

Explanation

To solve the problem, we need to demonstrate that the time required for 99% completion of a first-order reaction is twice the time required for 90% completion. Let's break this down step by step.

### Step 1: Understand the first-order reaction kinetics
For a first-order reaction, the rate of reaction is directly proportional to the concentration of the reactant. The integrated rate law for a first-order reaction is given by:

\[ t = \frac{1}{k} \ln \left(\frac{[A_0]}{[A_t]}\right) \]
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