In a pseudo first order hydrolysis of ester in water, the following results were obtained:

Calculate the pseudo first order rate constant for the hydrolysis of ester.

Explanation

Pseudo first order rate constant, k is given by
`k=( 2.303 )/( t) log (a)/( a-x)`
where a is the initial concentration and (a - x) is the concentration after time t.
` a= 0.55 M`
According to the given data:

The nearly constant values of k confirm that the reaction is of first order and the actual value of rate constant can be obtained by taking the average value of the rate constants `k_1 k_2 and k_3`
` k=( k_1 + k_2 + k_3 )/( 3) = ( ( 1.91 + 1.95 + 2.06)xx 10^(-2))/( 3)`
` = 1.97 xx 10^(-2) s^(-1) `