The activation energy for a first order reaction is 60 kJ `mol^(-1)` in the absence of a catalyst and 50 kJ `mol^(-1)` in the presence of a catalyst. How many times will the rate of reaction grow in the presence of the catalyst if the reaction proceeds at `27^@ `C ?

Answer

`55.06 ` times

Explanation

`log"" (k_2)/(k_1) = (1)/(2.303 RT) [E_1 -E_2] = (1)/(2.303 xx 8.314 xx 300)`
`[60-50 ] xx 10^3 =1.7409 = 55.06`
thus the rate of reaction grows 55.06 times in presence of the catalyst