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Identify the order of the reaction from ...

Identify the order of the reaction from the rate constant value `= 3.2 xx 10^(-5) L mol^(-1) s^(-1)`.

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To determine the order of the reaction from the given rate constant value, we can follow these steps: ### Step 1: Understand the Units of the Rate Constant The rate constant \( K \) has units that depend on the order of the reaction. For a reaction of order \( n \), the units of the rate constant \( K \) are given by: \[ \text{Units of } K = \text{mol}^{1-n} \cdot \text{L}^{-1} \cdot \text{s}^{-1} \] ...
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Identify the reaction order from each of the following rate constants (i) k= 3 xx 10^(-5) s^(-) (ii) k=9 xx 10^(-4) mol ^(-) "litre "s^(-) (iii) k= 6 xx 10^(-2) litre mol ^(-) s^(-) (iv) k= 2.3 xx 10^(-5) L mol ^(-1) s^(-1) (v) k= 3 xx 10^(-3) mol L^(-1) s^(-1)

Identify the reaction order from each of the following rate constants. (i) k = 2.3xx10^(-5)Lmol^(-1)s^(-1) (ii) k = 3xx 10^(-4)s^(-1)

Identify the reaction order from each of the following rate : k=2.3 xx 10^5 L mol^(-1) s^(-1)

Identify the reaction order form each of the following rate constants: a. k = 7.06 xx 10^(-3) mol L^(-1) s^(-1) b. k = 5.6 xx 10^(-5) s^(-1) c. k = 1.25 xx 10^(-2) mol^(-1)l s^(-1) d. k = 1.25 xx 10^(-2) mol L^(2)s^(-1) e. k = 5.0 xx 10^(-6) atm^(-1)s^(-1)

The decomposition of NH_(3) on Pt surface is a zero order reaction. If the value of rate constant is 2 xx 10^(-4)" mole liter"^(-1)" sec"^(-1) . The rate of appearance of N_(2) and H_(2) are respectively {:(" N"_(2)," H"_(2)),("(1) "1xx10^(-4)" mol l"^(-1)"sec"^(-1),3xx10^(-4)" mol"^(-1)"sec"^(-1)),("(2) "3xx10^(-4)" mol l"^(-1)"sec"^(-1),1xx10^(-4)" mol"^(-1)"sec"^(-1)),("(3) "2xx10^(-4)" mol l"^(-1)"sec"^(-1),6xx10^(-4)" mol"^(-1)"sec"^(-1)),("(4) "3xx10^(-4)" mol l"^(-1)"sec"^(-1),3xx10^(-4)" mol"^(-1)"sec"^(-1)):}

Identify the reaction order if the unit of rate constant is s^(-1) .

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