The reaction `N_2O_5 to 2NO_2 + 1/2 O_2` is of first order in `N_2 O_5`. Its rate constant is `6.2 xx 10^(-6) s^(-)`. If in the beginning, `[N_2 O_5]` is 15 mol `L^(-)` , calculate the rate of reaction in the beginning.

Answer

`9.3 xx 10^(-5) mol L^(-1) s^(-1)`

Explanation

For first order reaction,
` N_2 O_5 to 2NO_2 +1/2 O_2 , r = k [N_2 O_5]`
`= 6.2 xx 10^(-6) s^(-1) xx 15 mol L^(-1)`
`=9.3 xx 10^(-5) mol L^(-1) s^(-1)`