Consider the following first order reaction.
` 2H_2 O_2 (aq) overset(I^(-) (aq))to 2H_2 O (l) +O_2 (g)`
If the rate constant of the reaction is `1.01 xx 10^(-2) min^(-)`
What concentration of `H_2 O_2` would give rate of `1.12 xx 10^(-2) mol L^(-) min^(-) ?`

Answer

`1.11 mol L^(-1) `

Explanation

`r=k [H_2 O_2]or 1.12 xx 10^(-2) mol L^(-1) min""^(-1)`
`=1.01 xx 10^(-2) min ^(-1) [H_2 O_2]`
` or [H_2 O_2 ]=(1.12 xx 10^(-2) mol L^(-1) min""^(-1))/( 1.01 xx 10^(-2) min ^(-1))`
` = 1.11 mol L^(-1)`