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For a reaction, the energy of activation...

For a reaction, the energy of activation is zero. What is the value of rate constant at 300 K, if `k= 1.6 xx 10^6 s^(-1)` at 280 K?

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The correct Answer is:
`k_1 =k_2 = 1.6 xx 10^6 s^(-1)`
`E_a =0 " " therefore log "" (k_2)/(k_1)=0 or k_2 =k_1`
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