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The rate law for the reaction: Ester+H^(...

The rate law for the reaction: Ester+`H^(+)` Acid + Alcohol is
` (dx)/(dt) = k ` [Ester ]`[H^(+)]^(0)`
What would be the effect on the rate if
concentration of ester is doubled

Text Solution

Verified by Experts

No effect on rate.
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