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The decomposition of a hydrocarbon follo...

The decomposition of a hydrocarbon follows the equationk `= (4.5 xx 10 ^(11) s^(-1) )e^(-28000) K/T.` Calculate `E_a`.

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The correct Answer is:
`232.8 KJ mol^(-1)`
`k= (4.5 xx 10^(11) s^(-1) ) xx e^(-28000) K//T `
comparing it with Arrhenius equation
`k= Ae^(-E_a //RT) , (-E_a )/(RT) = ( - 28000 K) /(T)`
or `E_a =28000 K xx R = 28000 K xx 8.314 JK^(-1)`
` = 232792 J mol^(-1) = 232.8 KJ mol^(-1)`
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