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1" N m"^(-2) = dyne "cm"^(-2)...

`1" N m"^(-2)` = dyne `"cm"^(-2)`

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To convert \(1 \, \text{N/m}^2\) into \(\text{dyne/cm}^2\), we can follow these steps: ### Step 1: Understand the relationship between Newtons and dynes 1 Newton (N) is equivalent to \(10^5\) dynes (dyn). This is the first conversion we need. ### Step 2: Understand the relationship between square meters and square centimeters 1 meter (m) is equivalent to 100 centimeters (cm). Therefore, when we square this conversion: \[ 1 \, \text{m}^2 = (100 \, \text{cm})^2 = 10^4 \, \text{cm}^2 \] ### Step 3: Combine the conversions Now, we can combine the conversions from step 1 and step 2 to convert \(1 \, \text{N/m}^2\) to \(\text{dyne/cm}^2\): \[ 1 \, \text{N/m}^2 = \frac{10^5 \, \text{dyn}}{10^4 \, \text{cm}^2} \] ### Step 4: Simplify the expression Now, we simplify the fraction: \[ 1 \, \text{N/m}^2 = \frac{10^5}{10^4} \, \text{dyne/cm}^2 = 10^{5-4} \, \text{dyne/cm}^2 = 10^1 \, \text{dyne/cm}^2 = 10 \, \text{dyne/cm}^2 \] ### Final Answer Thus, we conclude that: \[ 1 \, \text{N/m}^2 = 10 \, \text{dyne/cm}^2 \] ---
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