A cauboid of volume `20 mxx 10 m xx 5m` has density `3 kg m^(-3)` .Find the maximum pressure exerted by cuboid on the surface .
Text Solution
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The correct Answer is:
600 Pa
Density = 3 `"kgm"^(-3)` Volume of cuboid `=lxxbxxh=20xx10xx5=10^(3)m^(2)` Mass of cuboid = Density `xx` Volume `=3xx10^(3)" kg"` Weight of cuboid `=mg=3xx10^(4)N` `A_(1)=200" m"^(2),A_(2)=50" m"^(2)`, `A_(3)=100" m"^(2)` Pressure `prop(1)/("Area")` that means the position of cuboid to give maximum bottom pressure is `P=(3xx10^(4))/(50)=0.6xx10^(3)=600" Pa"`
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