If a force of 10 N can accelerate a body of mass 'm' by `1 ms^(-2)` , then a force of 100 N can accelerate the same body by`"_______"`.
A
`10" ms"^(-2)`
B
`1" ms"^(-2)`
C
`100" ms"^(-2)`
D
`0.1" ms"^(-2)`
Text Solution
Verified by Experts
The correct Answer is:
A
Given `F_(1)=10N` `a_(1)=1" ms"^(-2)` `F_(2)=100" N"` `a_(2)=?` Since mass is same, `(F_(1))/(F_(2))=(a_(1))/(a_(2))` `:.(10)/(100)=(1)/(a^(2))rArra_(2)=10" ms"^(-2)` Hence, the correct option is (a)
Topper's Solved these Questions
AMAZING AIR
PEARSON IIT JEE FOUNDATION|Exercise Very short Answer Type Questions|20 Videos
AMAZING AIR
PEARSON IIT JEE FOUNDATION|Exercise Short Answer Type Questions|29 Videos
When a force of 1N acts on a body of mass 1 gram, the body receives an acceleration of
What mass of a body can attain an acceleration of 5 ms^(-2) under a force of 250N ?
A force of 150N produces an acceleration of 2ms^(-2) in a body and a force of 200N produces an acceleration of 3ms^(-2) The mass of the body and the coefficinent of kinetic friction are .
A force produces an acceleration of 4ms^(-2) in a body of mass m_(1) and the same force produces an acceleration of 6ms^(-2) in another body oa mass m_(2) . If the same force is applied to (m_(1)+m_(2)) , then the acceleration will be
When a horizontal force of 200N is applied on a body,the acceleration product in it Is 1.5ms^(-2) .When the force is 300N ,acceleration produced in the same body is 2.5ms^(-2) .Then mass of the body is (A) 200Kg, (B) "150Kg(C) 100Kg, (D) "50Kg