The length (16 cm) and area of cross section `(4 cm^(2))` of a copper wire are increased by 25% each. If the resistance of original wire is `8 Omega`, find the new resistance.

Explanation

(i) `R prop (l)/A`
(ii) `(R_1)/(R_2 ) =(l_1)/(l_2) xx (A_2)/(A_1)`
(iii) `l_2 = l_1 + 0.25 l_1`
`A_2 = A_1 + 0.25 A_1`
(iv) `8 Omega `