A body moving with a velocity of `10ms^(-1)` increases its velocity to `20ms^(-1)` in 2 s. Then the rate of change in velocity is ______.

Explanation

To find the rate of change in velocity (which is acceleration) of a body that increases its velocity from \(10 \, \text{m/s}\) to \(20 \, \text{m/s}\) in \(2 \, \text{s}\), we can follow these steps:

### Step 1: Identify the initial and final velocities
- The initial velocity (\(v_0\)) is given as \(10 \, \text{m/s}\).
- The final velocity (\(v_f\)) is given as \(20 \, \text{m/s}\).

### Step 2: Calculate the change in velocity
- The change in velocity (\(\Delta v\)) can be calculated using the formula:
...