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Describe the experimental method to dete...

Describe the experimental method to determine the time period of a simple pendulum.

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What is the time period of a simple pendulum ?

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Knowledge Check

  • The period of simple pendulum

    A
    increases with decreases in length
    B
    increases with increases in length
    C
    increases with keeping length constant
    D
    decrease with decrease in acceleration due to gravity

  • Time period of simple pendulum is

    A
    `T = 2pi sqrt(l/g)`
    B
    `T = 2pi sqrt(g/l)`
    C
    `T = sqrt(2 pi (l)/(g))`
    D
    `T = (1)/(2pi) sqrt(g/l)`

  • As the acceleration due to gravity increases, the time period of the simple pendulum_______

    A
    increases
    B
    decreases
    C
    remains same
    D
    first increases and then decreases.

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    A simple pendulum makes 20 oscillations in one second on the surface of the earth. Determine the time period of the simple pendulum on the surface of a planet where the acceleration due to gravity is one fourth of the acceleration due to gravity on the surface of the earth.

    The time period of simple pendulum inside a stationary lift is T. If lift starts accelerating upwards with the acceleration of g/2, then the new time period of the simple pendulum will be

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    Write down the steps to verify the third law of simple pendulum in a proper sequence. (a) Set the pendulum into ostillation and determine the time taken for 20 oscillations (b) Determine the square of the time period (T^(2)) (c) Change the length of the simple pendulum and repeat the experiment (d) Determine the time period of oscillation (T) (e) Determine the length of the pendulum (f) Note the value of V = (lamda)/(T) in each case

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