A light ray from an object 'P' is reflected from a mirror as shown in the figure, then

Options

A. angle of incidence is `30^@`
B. `PM = MP^1 `
C. `angle PON = 120^@`
D. All of the above

Answer

D

Explanation

From figure
` angle TON = 90^@`
` therefore angle TOQ = angle r =90^@ - 60^@ = 30^@`
` therefore ` angle of reflection ` = 30^@`
But according to the laws of reflection, the angle of incidence (i) = the angle of reflection (r).
` therefore i = 30^@`
(ii) In case of a plane mirror, object distance = image distance.
(iii) `anglePON = anglePOQ + angleQON`
` = angle POT + angle TOQ + angle QON`
` = 30^@ + 30^@ + 60^@`
` = 120^@`