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The following are the steps inolved in converting `0.bar(23)` into p/q form where `q!=0`. Arrange them in sequential order from the first to the last.
A. `:.100x=23.23 23 23` ……….2
B.As periodicity is 2, multiply the Eq. 2 with 100.
C.`:.99x=23impliesx=23/99`
D. Let `x=0.bar(23)=0.23 23 23`........1
E. Subtract Eq. 1 from Eq 2

A

DBEAC

B

DBAEC

C

DBCAE

D

DABEC

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AI Generated Solution

The correct Answer is:
To convert the repeating decimal \(0.\overline{23}\) into the form \( \frac{p}{q} \), we can follow these steps in the correct order: ### Step-by-Step Solution: 1. **Let \( x = 0.\overline{23} = 0.232323...\)** (This is Step D) - We start by defining \( x \) as the repeating decimal. 2. **Multiply both sides by 100** (This is Step B) - Since the decimal repeats every two digits, we multiply by \( 100 \) to shift the decimal point two places to the right: \[ 100x = 23.232323... \] 3. **Subtract the first equation from the second equation** (This is Step E) - Now we subtract the first equation from the second: \[ 100x - x = 23.232323... - 0.232323... \] This simplifies to: \[ 99x = 23 \] 4. **Solve for \( x \)** (This is Step C) - Now we can solve for \( x \): \[ x = \frac{23}{99} \] 5. **Final Result**: - We have successfully converted \( 0.\overline{23} \) into the fraction \( \frac{23}{99} \). ### Sequential Order of Steps: - D: Let \( x = 0.\overline{23} = 0.232323...\) - B: Multiply both sides by 100 - E: Subtract the first equation from the second equation - C: Solve for \( x \)
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