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If (3x)/5+5/(2x)=4, then find (9x^(2))/2...

If `(3x)/5+5/(2x)=4`, then find `(9x^(2))/25 + 25/(4x^(2))`

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To solve the equation \(\frac{3x}{5} + \frac{5}{2x} = 4\) and find the value of \(\frac{9x^2}{25} + \frac{25}{4x^2}\), we can follow these steps: ### Step 1: Square both sides of the equation We start with the equation: \[ \frac{3x}{5} + \frac{5}{2x} = 4 \] Now, we square both sides: \[ \left(\frac{3x}{5} + \frac{5}{2x}\right)^2 = 4^2 \] This gives us: \[ \left(\frac{3x}{5} + \frac{5}{2x}\right)^2 = 16 \] ### Step 2: Expand the left side using the formula for \((a + b)^2\) Using the formula \((a + b)^2 = a^2 + b^2 + 2ab\), we can expand the left side: \[ \left(\frac{3x}{5}\right)^2 + \left(\frac{5}{2x}\right)^2 + 2\left(\frac{3x}{5}\right)\left(\frac{5}{2x}\right) = 16 \] ### Step 3: Calculate each term Calculating each term: 1. \(\left(\frac{3x}{5}\right)^2 = \frac{9x^2}{25}\) 2. \(\left(\frac{5}{2x}\right)^2 = \frac{25}{4x^2}\) 3. \(2\left(\frac{3x}{5}\right)\left(\frac{5}{2x}\right) = 2 \cdot \frac{3x \cdot 5}{5 \cdot 2x} = 2 \cdot \frac{3}{2} = 3\) Putting it all together, we have: \[ \frac{9x^2}{25} + \frac{25}{4x^2} + 3 = 16 \] ### Step 4: Isolate the expression we want to find Now, we can isolate \(\frac{9x^2}{25} + \frac{25}{4x^2}\): \[ \frac{9x^2}{25} + \frac{25}{4x^2} = 16 - 3 \] This simplifies to: \[ \frac{9x^2}{25} + \frac{25}{4x^2} = 13 \] ### Final Answer Thus, the value of \(\frac{9x^2}{25} + \frac{25}{4x^2}\) is: \[ \boxed{13} \]
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