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Find the value of x, if 4:3 = x^(2):27. ...

Find the value of x, if `4:3 = x^(2):27. (x gt 0)` .

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PEARSON IIT JEE FOUNDATION-RATIO AND ITS APPLICATIONS-CONCEPT APPLICATION (LEVEL 1)
  1. Find the value of x, if 4:3 = x^(2):27. (x gt 0) .

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  2. If x:y = 1:1, then (3x+4y)/(5x+6y) = .

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  3. If x = 100, then 120% of x =.

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  4. 40% of 150 + 60% of 150 = .

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  5. Interest = Amount -.

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  6. If a = 2b, then a:b = .

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  7. If a person travels 60 km in 4 h in a car, then the speed of the car i...

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  8. 1 km/h = m/s.

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  9. If a person travels 150 km in 5 h, then he travels 180 km inh.

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  10. Distance covered by a car with 45 km/h in 2 h is.

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  11. If a train 100 m long takes 10 s to cross a telegraph post, then how m...

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  12. If six men can do a piece of work in 6 days, then 3 men can do same...

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  13. IF A can do a work in 10 days, then A's one day work is.

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  14. If B can do three-fourth of a work in 3 days, then the time taken to c...

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  15. If A can type 60 letters in a minute and B can type 120 letters in a m...

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  16. If X can do a piece of work in n days, then X's p days' work is.

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  17. Find the value of x, if 80:60 = x:12.

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  18. If x : y=2:3\ a n dy : z=2:3,\ then x : z= 2:3 (b) 3:4 (c) 5:7...

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  19. The cost of 30 mangoes is Rs. 150. What is the cost of 60 mangoes (in ...

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  20. 50% of 150 + 70% of 300 =

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  21. 55% " of " 1000 divide 60% " of " 2000 =?

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