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A pipe can fill an empty tank in 12 h. A...

A pipe can fill an empty tank in 12 h. After it is kept open for 3 h, another pipe which can fill the tank in 8 h is opened. In how many more hours will the tank be filled?

A

`17/7h`

B

`18/5h`

C

`20/9h`

D

`16/5h`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of how many more hours it will take to fill the tank after both pipes are opened, we can follow these steps: ### Step 1: Determine the filling rates of both pipes. - Pipe 1 can fill the tank in 12 hours. Therefore, the rate of Pipe 1 (P1) is: \[ \text{Rate of P1} = \frac{1}{12} \text{ tank per hour} \] - Pipe 2 can fill the tank in 8 hours. Therefore, the rate of Pipe 2 (P2) is: \[ \text{Rate of P2} = \frac{1}{8} \text{ tank per hour} \] ### Step 2: Calculate the volume filled by Pipe 1 in 3 hours. - In 3 hours, Pipe 1 will fill: \[ \text{Volume filled by P1 in 3 hours} = 3 \times \frac{1}{12} = \frac{3}{12} = \frac{1}{4} \text{ of the tank} \] ### Step 3: Determine the remaining volume to be filled. - The total volume of the tank is 1 (whole tank). After 3 hours, the remaining volume is: \[ \text{Remaining volume} = 1 - \frac{1}{4} = \frac{3}{4} \text{ of the tank} \] ### Step 4: Calculate the combined filling rate when both pipes are open. - The combined rate of both pipes (P1 and P2) is: \[ \text{Combined rate} = \frac{1}{12} + \frac{1}{8} \] - To add these fractions, find a common denominator (which is 24): \[ \frac{1}{12} = \frac{2}{24} \quad \text{and} \quad \frac{1}{8} = \frac{3}{24} \] - Therefore, \[ \text{Combined rate} = \frac{2}{24} + \frac{3}{24} = \frac{5}{24} \text{ tank per hour} \] ### Step 5: Calculate the time needed to fill the remaining volume. - Let \( t \) be the time in hours needed to fill the remaining \(\frac{3}{4}\) of the tank. Using the formula: \[ \text{Volume filled} = \text{Rate} \times \text{Time} \] - We have: \[ \frac{3}{4} = \frac{5}{24} \times t \] - To find \( t \), rearrange the equation: \[ t = \frac{3/4}{5/24} = \frac{3}{4} \times \frac{24}{5} = \frac{3 \times 24}{4 \times 5} = \frac{72}{20} = \frac{18}{5} \text{ hours} \] ### Step 6: Convert the time into a mixed number. - The time \( \frac{18}{5} \) hours can be expressed as: \[ \frac{18}{5} = 3 \frac{3}{5} \text{ hours} \] ### Final Answer: The tank will be filled in \( \frac{18}{5} \) hours or \( 3 \frac{3}{5} \) hours after both pipes are opened. ---
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