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If n (X) = 10 , n(Y) = 5 , and the sets ...

If n (X) = 10 , n(Y) = 5 , and the sets X and Y are dijoint , then find `n(X cup Y)` .

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To solve the problem, we need to find the number of elements in the union of two disjoint sets, X and Y. ### Step-by-Step Solution: 1. **Identify the number of elements in each set:** - We are given that \( n(X) = 10 \) (the number of elements in set X). - We are also given that \( n(Y) = 5 \) (the number of elements in set Y). 2. **Understand the concept of disjoint sets:** - Disjoint sets are sets that have no elements in common. This means that the intersection of the two sets is empty. - Therefore, \( n(X \cap Y) = 0 \). 3. **Use the formula for the union of two sets:** - The formula for the number of elements in the union of two sets is given by: \[ n(X \cup Y) = n(X) + n(Y) - n(X \cap Y) \] - Since \( n(X \cap Y) = 0 \) for disjoint sets, the formula simplifies to: \[ n(X \cup Y) = n(X) + n(Y) \] 4. **Substitute the values into the formula:** - Now, substitute the known values into the simplified formula: \[ n(X \cup Y) = 10 + 5 \] 5. **Calculate the result:** - Performing the addition gives: \[ n(X \cup Y) = 15 \] ### Final Answer: The number of elements in the union of sets X and Y is \( n(X \cup Y) = 15 \). ---
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