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The HCF of polynomials x^(3)-1 and x^(2)...

The HCF of polynomials `x^(3)-1 and x^(2)-1` is __________.

A

`x-1`

B

`x+1`

C

`x^(2)-x+1`

D

1

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The correct Answer is:
To find the HCF (Highest Common Factor) of the polynomials \( x^3 - 1 \) and \( x^2 - 1 \), we can follow these steps: ### Step 1: Factor the polynomials First, we will factor both polynomials using the known formulas. 1. **Factor \( x^3 - 1 \)**: The expression \( x^3 - 1 \) can be factored using the formula for the difference of cubes: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \] Here, \( a = x \) and \( b = 1 \): \[ x^3 - 1 = (x - 1)(x^2 + x + 1) \] 2. **Factor \( x^2 - 1 \)**: The expression \( x^2 - 1 \) can be factored using the difference of squares formula: \[ a^2 - b^2 = (a - b)(a + b) \] Here, \( a = x \) and \( b = 1 \): \[ x^2 - 1 = (x - 1)(x + 1) \] ### Step 2: Identify the common factors Now we have the factored forms: - \( x^3 - 1 = (x - 1)(x^2 + x + 1) \) - \( x^2 - 1 = (x - 1)(x + 1) \) The common factor in both expressions is \( (x - 1) \). ### Step 3: Determine the HCF The HCF of the two polynomials is the highest common factor that we identified: \[ \text{HCF} = x - 1 \] ### Final Answer The HCF of the polynomials \( x^3 - 1 \) and \( x^2 - 1 \) is \( \boxed{x - 1} \). ---
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PEARSON IIT JEE FOUNDATION-POLYNOMIALS, LCM AND HCF OF POLYNOMIALS -CONCEPT APPLICATION (LEVEL 1)
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