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The HCF of the polynomials (x^(3)-9^(3))...

The HCF of the polynomials `(x^(3)-9^(3))(x+3) and (x^(2)-9)(x^(2)-3)` is ____________.

A

`x+sqrt(3)`

B

`x-9`

C

`x+3`

D

`x-3`

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The correct Answer is:
To find the HCF (Highest Common Factor) of the polynomials \((x^3 - 9^3)(x + 3)\) and \((x^2 - 9)(x^2 - 3)\), we will follow these steps: ### Step 1: Factor the first polynomial The first polynomial is \((x^3 - 9^3)(x + 3)\). We can factor \(x^3 - 9^3\) using the difference of cubes formula: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \] Here, \(a = x\) and \(b = 9\). So, \[ x^3 - 9^3 = (x - 9)(x^2 + 9x + 81) \] Thus, the first polynomial becomes: \[ (x - 9)(x^2 + 9x + 81)(x + 3) \] ### Step 2: Factor the second polynomial The second polynomial is \((x^2 - 9)(x^2 - 3)\). We can factor \(x^2 - 9\) using the difference of squares formula: \[ a^2 - b^2 = (a - b)(a + b) \] Here, \(a = x\) and \(b = 3\). So, \[ x^2 - 9 = (x - 3)(x + 3) \] The second polynomial becomes: \[ (x - 3)(x + 3)(x^2 - 3) \] ### Step 3: Write down the complete factorizations Now we have: 1. First polynomial: \((x - 9)(x^2 + 9x + 81)(x + 3)\) 2. Second polynomial: \((x - 3)(x + 3)(x^2 - 3)\) ### Step 4: Identify the common factors Now, we will identify the common factors in both factorizations: - From the first polynomial, we have \(x + 3\). - From the second polynomial, we also have \(x + 3\). ### Step 5: Determine the HCF The only common factor between the two polynomials is \(x + 3\). Therefore, the HCF of the given polynomials is: \[ \text{HCF} = x + 3 \] ### Final Answer The HCF of the polynomials \((x^3 - 9^3)(x + 3)\) and \((x^2 - 9)(x^2 - 3)\) is \(\boxed{x + 3}\). ---
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PEARSON IIT JEE FOUNDATION-POLYNOMIALS, LCM AND HCF OF POLYNOMIALS -CONCEPT APPLICATION (LEVEL 2)
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