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Find the HCF of the polynomials 6(x^(2)-...

Find the HCF of the polynomials `6(x^(2)-36) and 36(x+6)`.

A

`6(x+6)`

B

`6(x-6)`

C

`(x+6)`

D

`(x-6)`

Text Solution

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The correct Answer is:
To find the HCF (Highest Common Factor) of the polynomials \(6(x^2 - 36)\) and \(36(x + 6)\), we will follow these steps: ### Step 1: Factor the first polynomial The first polynomial is \(6(x^2 - 36)\). We can factor \(x^2 - 36\) using the difference of squares formula, which states that \(a^2 - b^2 = (a + b)(a - b)\). \[ x^2 - 36 = (x + 6)(x - 6) \] Thus, we can rewrite the first polynomial as: \[ 6(x^2 - 36) = 6((x + 6)(x - 6)) = 6(x + 6)(x - 6) \] ### Step 2: Factor the second polynomial The second polynomial is \(36(x + 6)\). We can factor \(36\) as \(6 \times 6\): \[ 36(x + 6) = 6 \cdot 6(x + 6) \] ### Step 3: Identify the common factors Now we have the factored forms of both polynomials: 1. \(6(x + 6)(x - 6)\) 2. \(6 \cdot 6(x + 6)\) Next, we identify the common factors in both expressions. - The common factor in both polynomials is \(6\). - The term \((x + 6)\) is also common in both. ### Step 4: Write the HCF The HCF is the product of the common factors: \[ \text{HCF} = 6(x + 6) \] ### Final Answer Thus, the HCF of the polynomials \(6(x^2 - 36)\) and \(36(x + 6)\) is: \[ \text{HCF} = 6(x + 6) \] ---
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PEARSON IIT JEE FOUNDATION-POLYNOMIALS, LCM AND HCF OF POLYNOMIALS -CONCEPT APPLICATION (LEVEL 2)
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