Home
Class 12
CHEMISTRY
The electrical resistance of a column of...

The electrical resistance of a column of 0.05 M NaOH solution of diameter 1 cm and length 50 cm is 5.55 `xx 10^(3) Omega`. Calculate its resistivity, conductivity and molar conductivity.

Text Solution

Verified by Experts

Area, `A = pi r^(2) = 3.14 xx (( 1)/( 2))^(2) cm^(2) = 0.785 cm^(2)`
Resistivity, `rho = ( RA)/( l )`
` = ( 5.55 xx 10^(3) xx 0.785 cm^(2))/( 50 cm ) = 87. 135cm`
Conductivity, `k = ( 1)/( r ) = ( 1)/( 87.135) Omega^(-1) cm^(-1) = 0.01148 `
`= 1.148 xx 10^(-2) S cm^(-1) Omega^(-1) cm^(-1)`
Molar conductivity,
`Lambda_(m) = ( k xx 1000)/( M ) = ( 1.1 48xx 10^(-2) xx 1000)/( 0.05)`
`= 229.6 S cm^(2) " mol"^(-1)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise SAMPLE QUESTION (PART III)|4 Videos
  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR PRACTICE (PART 1) ( CONDUCTOR ELECTROLYTES AND THEIR DISSOCIATION, ELECTROLYSIS, ITS LAW AND APPLICATIONS)(MULTIPLE CHOICE TYPE QUESTIONS) |4 Videos
  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( LONG ANSWER TYPE QUESTIONS) |3 Videos
  • D-BLOCK ELEMENTS

    ARIHANT PUBLICATION|Exercise Chapter practice (Long answer type questions)|2 Videos
  • ELEMENTS : NITROGEN FAMILY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( Long Answer Type Questions ) |11 Videos

Similar Questions

Explore conceptually related problems

The resistance of a conductivity cell when filled with 0.05M solution of an electrolyte x is 100 Omega at 40^(@)C . The same conductivity cell filled with 0.01M solution of electrolyte y has a resistance of 50 Omega . The conductivity of 0.05 M solution of electrolyte x is 1.0 xx 10^(-4) S cm^(-1) . Calculate (i) cell constant (ii) conductivity of 0.01 M solution (iii) molar conductivity of 0.01 M solution

The specific conductivity of 0.12N solution of an electrolyte is 2.4 xx 10^(-2)S cm^(-1) . Calculate its equivalent conductance.

A wire of diameter 1 mm has a resistance of 14 omega . If the resistivity of its material is 44 xx 10^(-6) omega -cm, calculate its length.

The specific conductance of a 0.12N solution of an electrolyte is 2.4xx10^-2 ohm^-1cm^-1 Calculate its equivalent conductance.

Resistance of a conductivity cell filled with 0.1 M KCl solution is 100 ohms. If the resistance of the same cell when filled with 0.02 M KCl solution is 520 ohms, calculate the conductivity and molar conductivity of 0.02 M KCl solution. (The conductivity of 0.1 M KCl solution is 1.29 Sm^(-1) ).

The conductivity of 0.20 M solution of KCl at 298 K is 0.248S cm^(-1) . Calculate its molar conductivity.

The conductivity of a 0.20 M solution of KCl at 298 K is 0.0248 S cm^(-1) . Calculate its molar conductivity.

Specific conductance of a 0.12 N solution of electrolyte is 2.4 xx 10^(-2) "ohm^(-1) cm^(-1) . What is the value of its equivalent conductance?

The resistance of a metal wire of length 1m is 3 ohm. The diameter of the wire is 0.2 m. Calculate the resistivity of the metal at the temperature.

An external field of 1000 Volt /m maintains a current density of 0.1 Amp/m^2 . Calculate (a) the resistivity (b) the conductivity.