Home
Class 12
CHEMISTRY
Write the Nernst equation for the electr...

Write the Nernst equation for the electrode reaction.
`M^(n+) ( aq) + n e^(-) rarr M(s)`
`E = E^(@) - ( 2.303 RT )/( nF ) log""( [ M ] )/([ M ^(n+)])`

Text Solution

Verified by Experts

From Nernst equation, `E = E^(@) - ( 2.303 RT)/( nR) log"" ( [ M ] )/( [M^(n+)])`
For solid, M concentration is taken as unity
Hence, `E = E^(@) + ( 2.303 RT)/( nF ) log [ M^(n+)]`
Promotional Banner

Topper's Solved these Questions

  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR PRACTICE (PART 1) ( CONDUCTOR ELECTROLYTES AND THEIR DISSOCIATION, ELECTROLYSIS, ITS LAW AND APPLICATIONS)(MULTIPLE CHOICE TYPE QUESTIONS) |4 Videos
  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise QUESTIONS FOR PRACTICE (PART 1) ( CONDUCTOR ELECTROLYTES AND THEIR DISSOCIATION, ELECTROLYSIS, ITS LAW AND APPLICATIONS)(VERY SHORT ANSWER TYPE QUESTIONS) |8 Videos
  • ELECTROCHEMISTRY

    ARIHANT PUBLICATION|Exercise SAMPLE QUESTION (PART II)|3 Videos
  • D-BLOCK ELEMENTS

    ARIHANT PUBLICATION|Exercise Chapter practice (Long answer type questions)|2 Videos
  • ELEMENTS : NITROGEN FAMILY

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE ( Long Answer Type Questions ) |11 Videos

Similar Questions

Explore conceptually related problems

Write the Nernst equation for electrode reaction. M^(n+) (aq) + n e^(-) rarr M(s)

Write the Nernst equation for the electrode reaction: Cu_(aq)^(2+) + 2e rarr Cu(s)

Derive the Nernst equation for the electrode potential of the electrode M^(n+) (aq) + n e^- rarr M(s)

Derive the Nernst equation of electrode potential at 25^(@) C for the electrode reaction. M^(+) ( aq) + n e hArr M (s)

What is the value of e/m for an electron ?

Calculate the half-cell potential at 298 K for the reaction Cu^(2+) ( aq) + 2e^(-) rarr Cu(s) where [ Cu^(2+) ] is 5.0 M and E^(@) is + 0.34 V

Write the Nernst equation and emf of the following cell at 298K. Fe(s) | Fe^(2+) ( 0.001M) || H^(+) ( 1M ) | H_(2) ( g) ( 1"bar") | Pt .

Write the Nernst equation and emf of the following cell at 298 K. (i) Mg(s) |Mg^(2+) ( 0.001 M) || Cu^(2+) ( 0.0001M ) | Cu(s) (ii) Fe(s) | Fe^(2+) ( 0.001M) || H^(+) ( 1M) | H_(2)(g) (1 "bar") | Pt(s) Given that, E_(Mg^(2+) //Mg)^(@) = - 2.36V , E_(Cu^(2+) Cu)^(@) = 0.34V, E_(Fe^(2+)Fe)^(@) = -0.44V