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Calculate Lambda^(@) for acetic acid, ...

Calculate `Lambda^(@)` for acetic acid,
Given that, `Lambda_((HCl))^(@)` = 426 S `cm^(2) "mol"^(_1)`
`Lambda_((NaCl))^(@) ` = 126 S `cm^(2) "mol"^(_1)`
`Lambda_((CH_(3) COONa))^(@) `= 91 S `cm^(2) "mol"^(-1)`
Recall Kohlrausch's law to find the conductance of weak electrolyte.

Text Solution

Verified by Experts

`Lambda_((CH_(3)COOH))^(@) = Lambda _(H)^(@) + Lambda_(CH_(3)COO^(-))^(@)`
`= Lambda_(H^(+))^(@) + Lambda_(Cl^(-))^(@) + Lambda_(CH_(3)COO^(-))^(@) + Lambda_(Na^(+))^(@) - Lambda_(Cl^(-))^(@) - Lambda_(Na^(+))^(@)`
`= Lambda_((HCl))^(@) + Lambda_((CH_(3)COONa))^(@) - Lambda_((NaCl))^(@)`
`= ( 426 + 91- 126 ) S cm^(2) "mol"^(-1)`
= 391 S `cm^(2) "mol"^(-1)`
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