Home
Class 12
CHEMISTRY
One gram of charcoal adsorbs 100 mL of 0...

One gram of charcoal adsorbs 100 mL of 0.5 M -acetic acid to form a monolayer and the molarity of acetic acid reduces to 0.49. Calculate the surface area of charcoal adsorbed by each molecule of acetic acid. The surface area of charcoal is `3.01xx 10^2 m^2 g^(-1)`.

Text Solution

Verified by Experts

Initial millimoles of `CH_3 COOH = 100 xx 0.5=50`
Final millimoles of `CH_3COOH = 100 xx 0.49= 49 `
Millimoles adsorbed = 50 - 49=1
Moles adsorbed =`(1)/(1000)`
Number of molecules adsorbed
` = ( 1)/(1000 ) xx 6.023 xx 10^(23)`
` = 6.023 xx 10^(20)`
Area per molecule `= (" Total area ")/("Number of molecules ")`
`= ( 3.01 xx 10^2)/( 6.023 xx 10^(20))`
` = 5 xx 10^(-19) m^2`
Promotional Banner

Topper's Solved these Questions

  • SURFACE CHEMISTRY

    ARIHANT PUBLICATION|Exercise PART-I QUESTIONS FOR PRACTICE ( SHORT ANSWER TYPE II QUESTIONS)|11 Videos

  • SURFACE CHEMISTRY

    ARIHANT PUBLICATION|Exercise PART-I QUESTIONS FOR ASSESSMENT (MULTIPLE CHOICE TYPE QUESTIONS)|3 Videos

  • SURFACE CHEMISTRY

    ARIHANT PUBLICATION|Exercise PART-I QUESTIONS FOR PRACTICE (VERY SHORT ANSWER TYPE QUESTIONS)|14 Videos

  • SAMPLE PAPER 5

    ARIHANT PUBLICATION|Exercise GROUP C |7 Videos

  • THE SOLID STATE

    ARIHANT PUBLICATION|Exercise CHAPTER PRACTICE (Long Answer Type Questions)|2 Videos

Similar Questions

Explore conceptually related problems

A water drop has a diameter of 2 xx 10^-5m . Calculate the excess pressure inside, compared to the outside, if the surface tension of water is 0.072 N/m

The equivalent conductance of 0.1 N acetic acid is 5 cm^2 ohm^-1 gm eq^-1 and at infinite dilution is 390 cm^2ohm^-1gm eq^-1 . Calculate the degree of dissociation of acetic acid.

Find the pH of a 0.01 M solution of acetic acid having degree of dissociation 12.5%.

Calculate the amount of acetic acid present in one litre, having degree of dissociation equal 1% and K_(a) = 1.8 xx 10^(-5) .

The conductivity of 0.001 M actic acid is 4 xx 10^(-5) S //cm . Calculate the dissociation constant acetic acid, if molar conductivity at infinite dilution for acetic acid is 390 S cm^(2) // mol.

50 ml of 2 N acetic acid mixed with 10 ml of 1N sodium acetate solution will have an approximate ph of (K_a=10^(-5))

The freezing point of a solution containing 0.3 g of acetic acid in 30 g of benzene is lowered by 0.45^@c . Calculate the Vant's hoff factor (K_f for benzene = 5.12 K kg mol^-1) .

Calculate PH Of 0.01 M acetic acid . K_a = 1.8 xx 10^-5 at 298 K.