Find the sum of the products of the corresponding terms of the sequences 2,4, 8, 16, 32 and 128, 32, 8, 2, `1/2`.

Explanation

let the first sequence is `a_n`

let the second sequence as `b_n`

we have to find `C_n = a_nb_n`

`= 256(2*1/4)^(n-1)`

`sum C_n = s_5= (256(1-(1/2)^5))/(1- 1/2)`

`= (256(1-1/32))/(1/2)`

`=(2*256*31)/32`

`= 16*31 = 496`

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