Complete oxidation of one gram mol. Of glucose gives rise to

Options

A. 6860,000 cal
B. 686,000 cal
C. 68,600 cal
D. 6,860 cal

Answer

To solve the question regarding the complete oxidation of one gram mole of glucose and the energy produced, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Glucose Oxidation**:
- The complete oxidation of glucose (C6H12O6) occurs during cellular respiration, primarily through aerobic respiration.

2. **Energy Yield from Glucose**:
- The complete oxidation of one mole of glucose yields approximately 686 kilocalories (kcal) of energy. This is a well-established value in biochemistry.

3. **Conversion of Kilocalories to Calories**:
- Since 1 kilocalorie (kcal) is equivalent to 1,000 calories, we can convert the energy yield from kilocalories to calories:
\[ 686 \text{ kcal} = 686 \times 1000 \text{ calories} = 686,000 \text{ calories} \]

4. **Identifying the Correct Option**:
- Now that we have calculated the energy yield in calories, we can compare it with the given options:
- Option 1: 68,60,000 kcal
- Option 2: 6,86,000 kcal
- Option 3: 68,600 kcal
- Option 4: 68,60 kcal
- The correct answer is Option 2: 6,86,000 kcal.

### Final Answer:
The complete oxidation of one gram mole of glucose gives rise to **686,000 kcal**.

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