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How many PGAL are produced by glycolysis...

How many PGAL are produced by glycolysis of three molecules of glucose ? How many ATP are released by respiration of these PGAL till formation of `CO_(2)" and "H_(2)O`

A

4 PGAL-40 ATP

B

6 PGAL-120 ATP

C

4 PGAL-80 ATP

D

5 PGAL-160 ATP

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question step by step, we will break down the process of glycolysis and the subsequent ATP production from the resulting PGAL (Phosphoglyceraldehyde) molecules. ### Step 1: Determine PGAL Production from Glucose 1. **Understand Glycolysis**: Glycolysis is the metabolic pathway that converts glucose into pyruvate, producing PGAL as an intermediate. 2. **PGAL Production**: Each molecule of glucose produces 2 molecules of PGAL during glycolysis. 3. **Calculate for Three Glucose Molecules**: If one molecule of glucose produces 2 PGAL, then three molecules of glucose will produce: \[ 3 \text{ glucose} \times 2 \text{ PGAL/glucose} = 6 \text{ PGAL} \] ### Step 2: Determine ATP Production from PGAL 1. **ATP Yield from PGAL**: The complete oxidation of PGAL through cellular respiration (including glycolysis, the Krebs cycle, and oxidative phosphorylation) yields a total of approximately 38 ATP per molecule of glucose. 2. **Relate PGAL to ATP**: Since 2 PGAL are produced from 1 glucose, we can deduce that: - 2 PGAL yield 38 ATP. - Therefore, 1 PGAL yields: \[ \frac{38 \text{ ATP}}{2 \text{ PGAL}} = 19 \text{ ATP/PGAL} \] 3. **Calculate for 6 PGAL**: Now, for 6 PGAL, the total ATP produced would be: \[ 6 \text{ PGAL} \times 19 \text{ ATP/PGAL} = 114 \text{ ATP} \] ### Conclusion - **Total PGAL Produced**: 6 PGAL from the glycolysis of three glucose molecules. - **Total ATP Released**: 114 ATP from the respiration of these 6 PGAL until the formation of CO₂ and H₂O. ### Final Answer: - **PGAL Produced**: 6 - **ATP Released**: 114
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