A plant with a genotype Aa Bb is crossed with a plant having the genotype aa bb. The genotype of `F_(1)` would be

Options

A. AaBb, AABB
B. aabb,aaBb
C. aaBB,AABb
D. AaBb,Aabb,aaBb, abab

Answer

To determine the genotype of the F1 generation from the cross between two plants with the genotypes Aa Bb and aa bb, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotypes of the Parents:**
- Parent 1: Aa Bb (heterozygous for both traits)
- Parent 2: aa bb (homozygous recessive for both traits)

2. **Determine the Gametes Produced by Each Parent:**
- For Parent 1 (Aa Bb), the possible gametes are:
- AB (from A and B)
- Ab (from A and b)
- aB (from a and B)
- ab (from a and b)
- For Parent 2 (aa bb), since it is homozygous recessive, the only gamete produced is:
- ab

3. **Set Up a Punnett Square:**
- We can create a Punnett square to visualize the combinations of gametes from both parents.
- The gametes from Parent 1 (Aa Bb) will be placed on the top, and the gamete from Parent 2 (aa bb) will be placed on the side.

```
ab
__________
| AB | Ab | aB | ab |
|______|______|______|______|
```

4. **Fill in the Punnett Square:**
- Now, we will fill in the Punnett square with the combinations of the gametes:
- The combinations will be:
- AB (from Aa Bb) with ab (from aa bb) → Aa Bb
- Ab (from Aa Bb) with ab (from aa bb) → Aa bb
- aB (from Aa Bb) with ab (from aa bb) → aa Bb
- ab (from Aa Bb) with ab (from aa bb) → aa bb

This results in the following genotypes for the F1 generation:
- Aa Bb
- Aa bb
- aa Bb
- aa bb

5. **Conclusion:**
- The genotypes of the F1 generation are:
- Aa Bb
- Aa bb
- aa Bb
- aa bb

### Final Answer:
The genotypes of the F1 generation will be Aa Bb, Aa bb, aa Bb, and aa bb.