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In an experiment on pea plant, pure plan...

In an experiment on pea plant, pure plants with yellow round seeds (YYRR) were crossed with plants producing green wrinkled seeds (yyrr). What will be phenotypic ratio of `F_(1)` progeny ?

A

9 yellow round : 3 round green : 3 wrinkled yellow : 1 green wrinkled

B

All yellow round

C

1 round yellow : 1 round green : 1 wrinkled yellow : 1 wrinkled green

D

All wrinkled green

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the cross between the two types of pea plants and determine the phenotypic ratio of the F1 progeny. ### Step-by-Step Solution: 1. **Identify the Genotypes of the Parents:** - The first parent has yellow round seeds, which is homozygous dominant for both traits: **YYRR**. - The second parent has green wrinkled seeds, which is homozygous recessive for both traits: **yyrr**. 2. **Determine the Gametes Produced by Each Parent:** - The gametes from the first parent (YYRR) can only be **YR** (since both alleles are the same). - The gametes from the second parent (yyrr) can only be **yr** (again, both alleles are the same). 3. **Perform the Cross:** - When we cross these two parents, we combine the gametes: - From YYRR (YR) and yyrr (yr), the F1 progeny will have the genotype **YyRr**. 4. **Determine the Phenotype of the F1 Progeny:** - Yellow (Y) is dominant over green (y), and round (R) is dominant over wrinkled (r). - Since the F1 progeny has at least one dominant allele for both traits (Y and R), the phenotype will be: - **Yellow Round Seeds**. 5. **Conclusion:** - All F1 progeny will exhibit the same phenotype, which is yellow round seeds. - Therefore, the phenotypic ratio of the F1 progeny is **1:0** (or simply all yellow round). ### Final Answer: The phenotypic ratio of the F1 progeny is **1:0** (all yellow round seeds). ---
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