A single heterozygous yellow wrinkled seeded Pea plant shall produced gametes

Options

A. YR only
B. yr only
C. Yr and yr
D. YR and yR

Answer

To determine the gametes produced by a single heterozygous yellow wrinkled seeded pea plant, we need to analyze the genetic makeup of the plant.

### Step-by-Step Solution:

1. **Identify the Genotype**:
- The plant is described as heterozygous for the yellow seed trait and homozygous for the wrinkled seed trait.
- Yellow seeds are represented by the alleles Y (dominant) and y (recessive). Since the plant is heterozygous, its genotype for seed color is Yy.
- Wrinkled seeds are represented by the allele r (recessive). Since the plant is homozygous for this trait, its genotype for seed shape is rr.

Therefore, the complete genotype of the plant is **Yy rr**.

2. **Determine Gamete Formation**:
- Gametes are formed through the process of meiosis, where alleles segregate so that each gamete receives one allele from each gene.
- For the genotype Yy rr, the gametes will consist of one allele for seed color (Y or y) and one allele for seed shape (r).

3. **List Possible Gametes**:
- The possible combinations of alleles for the gametes can be derived as follows:
- From Yy, we can have either Y or y.
- From rr, we can only have r (since both alleles are the same).
- Therefore, the possible gametes are:
- **Y r** (from Y and r)
- **y r** (from y and r)

4. **Final Answer**:
- The gametes produced by the heterozygous yellow wrinkled seeded pea plant are **Y r** and **y r**.

### Conclusion:
The correct answer is that the gametes produced are **Y r** and **y r**.

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