A cross between AA and aa will produce an `F_(1)` progeny
(a) Genotypically aa, phenotypically A
(b) Genotypically AA, phenotypically a
(c) Genotypically Aa, phenotypically A
(d) Genotypically Aa, phenotypically a

Options

A. Genotypically aa, phenotypically A
B. Genotypically AA, phenotypically a
C. Genotypically Aa, phenotypically A
D. Genotypically Aa, phenotypically a

Answer

To solve the question regarding the cross between AA and aa, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotypes of the Parents:**
- The first parent has the genotype **AA** (homozygous dominant).
- The second parent has the genotype **aa** (homozygous recessive).

2. **Determine the Gametes Produced by Each Parent:**
- The gametes produced by the AA parent can only be **A** (as both alleles are A).
- The gametes produced by the aa parent can only be **a** (as both alleles are a).

3. **Perform the Cross:**
- When we cross the gametes from both parents, we will combine them:
- From AA (A) and aa (a), the possible combinations for the offspring (F1 progeny) will be:
- A from AA and a from aa gives **Aa**.

4. **Determine the Genotype of the F1 Progeny:**
- All offspring will have the genotype **Aa**.

5. **Determine the Phenotype of the F1 Progeny:**
- Since A is dominant over a, the phenotype of the F1 progeny will express the dominant trait associated with A.
- Thus, the phenotype will be **A**.

6. **Conclusion:**
- Therefore, the F1 progeny will be **genotypically Aa** and **phenotypically A**.

### Final Answer:
The correct option is **(c) Genotypically Aa, phenotypically A**.

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