In Pisum sativum there are 14 Chromosomes. How many pairs with different chromosomal composition can be prepared

Options

A. `2^(14)`
B. `2^(7)`
C. 7
D. 14

Answer

To solve the problem of how many pairs with different chromosomal compositions can be prepared from 14 chromosomes in Pisum sativum, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Chromosome Count**:
- Pisum sativum (pea plant) has a total of 14 chromosomes. This means that there are 7 pairs of chromosomes since chromosomes are typically found in pairs.

2. **Identifying Chromosomal Pairs**:
- Each pair consists of two homologous chromosomes. Therefore, with 14 chromosomes, we can denote them as pairs: (C1, C2), (C3, C4), (C5, C6), (C7, C8), (C9, C10), (C11, C12), (C13, C14).

3. **Calculating Different Compositions**:
- Each pair of chromosomes can independently assort during gamete formation. This means that each pair can contribute either of its two chromosomes to a gamete.
- For 7 pairs of chromosomes, each pair can be combined in two ways (either one chromosome from the pair or the other).

4. **Using the Formula for Combinations**:
- The total number of different combinations of chromosomes can be calculated using the formula \(2^n\), where \(n\) is the number of pairs.
- Here, \(n = 7\), so we calculate \(2^7\).

5. **Final Calculation**:
- \(2^7 = 128\). Therefore, there are 128 different chromosomal compositions that can be formed from the 14 chromosomes in Pisum sativum.

### Conclusion:
The number of pairs with different chromosomal compositions that can be prepared from the 14 chromosomes in Pisum sativum is **128**.