Pea Plant with round Yellow seeds (RRYY) is crossed with another pea plant having wrinkled green seeds (rryy). `F_(2)` progeny consist of
(i) Heterozygous for both shape and colour of seeds -
(ii) Dominant for colour and recessive for shape -
(iii) Homozygous for both shape and colour -
(iv) Heterozygous for seed shape only -

Options

A. i-2, ii-4,iii-3,iv-8
B. i-4,ii-2,iii-3,iv-8
C. i-3,ii-4,iii-8,iv-2
D. i-4,ii-3,iii-2,iv-8

Answer

To solve the problem, we need to analyze the genetic cross between the two pea plants and determine the phenotypes and genotypes of the F2 progeny. Let's break it down step by step.

### Step 1: Identify the parental genotypes
The parental plants are:
- Plant 1: Round Yellow seeds (RRYY)
- Plant 2: Wrinkled Green seeds (rryy)

### Step 2: Determine the F1 generation
When we cross these two plants, we can determine the F1 generation:
- All offspring (F1) will be heterozygous for both traits: RrYy (Round Yellow seeds).

### Step 3: Perform a dihybrid cross for F2 generation
To find the F2 generation, we need to cross the F1 generation with itself:
- F1 Cross: RrYy x RrYy

### Step 4: Set up a Punnett square
We can set up a Punnett square for the dihybrid cross (RrYy x RrYy). The gametes produced by each parent will be:
- Parent 1 gametes: RY, Ry, rY, ry
- Parent 2 gametes: RY, Ry, rY, ry

### Step 5: Fill in the Punnett square
The resulting combinations will be:
- RRYY (Homozygous Round Yellow)
- RRYy (Heterozygous Round Yellow)
- RrYY (Heterozygous Round Yellow)
- RrYy (Heterozygous Round Yellow)
- Rryy (Heterozygous Round Green)
- rrYY (Homozygous Wrinkled Yellow)
- rrYy (Heterozygous Wrinkled Yellow)
- rryy (Homozygous Wrinkled Green)

### Step 6: Count the phenotypes
From the combinations, we can categorize the phenotypes:
1. Round Yellow (dominant): R_Y_ (includes RRYY, RRYy, RrYY, RrYy)
2. Round Green (dominant for shape, recessive for color): R_yy (includes Rryy)
3. Wrinkled Yellow (recessive for shape, dominant for color): rrY_ (includes rrYY, rrYy)
4. Wrinkled Green (recessive for both traits): rryy

### Step 7: Determine the specific counts
- Heterozygous for both shape and color (RrYy): 4
- Dominant for color and recessive for shape (Rryy): 3
- Homozygous for both shape and color (RRYY, rryy): 2
- Heterozygous for seed shape only (Rryy): 8

### Final Results
Thus, the F2 progeny consists of:
(i) Heterozygous for both shape and color of seeds: 4
(ii) Dominant for color and recessive for shape: 3
(iii) Homozygous for both shape and color: 2
(iv) Heterozygous for seed shape only: 8