In a plant cell, O.P. is equal to

Options

A. T.P.-D.P.D.
B. D.P.D.-T.P
C. T.P.-D.P.
D. D.P.D.+T.P.

Answer

To solve the question regarding the osmotic pressure (O.P.) in a plant cell, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Osmotic Pressure (O.P.):**
- Osmotic pressure is defined as the pressure required to stop the flow of water across a semipermeable membrane due to osmosis. It is a measure of the tendency of water to move into a solution.

2. **Identify Related Concepts:**
- **Diffusion Pressure Deficit (DPD):** This is the difference in diffusion pressure between two solutions and is influenced by the concentration of solute in the solution.
- **Turgor Pressure:** This is the pressure exerted by the fluid inside the cell against the cell wall. It is a result of the osmotic pressure and is crucial for maintaining cell structure.

3. **Use the Relationship Between O.P., DPD, and Turgor Pressure:**
- The relationship can be expressed as:
\[ \text{Osmotic Pressure (O.P.)} = \text{Diffusion Pressure Deficit (DPD)} + \text{Turgor Pressure} \]
- This equation indicates that osmotic pressure is the sum of the diffusion pressure deficit and the turgor pressure.

4. **Evaluate the Options:**
- Given the options:
1. Turgor Pressure - DPD
2. DPD - Turgor Pressure
3. Turgor Pressure - Diffusion Pressure
4. DPD + Turgor Pressure
- The correct option according to our derived formula is option 4: **DPD + Turgor Pressure**.

5. **Conclusion:**
- Therefore, in a plant cell, the osmotic pressure (O.P.) is equal to the sum of the diffusion pressure deficit and the turgor pressure.

### Final Answer:
- **O.P. = DPD + Turgor Pressure** (Correct option: 4)

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